0破剑式 (独孤九剑)
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- a1:=v/ma(v,5)>2.97 and v/ma(v,3)>0.7;
- a2:=c/hhv(h,120)>0.958;
- a3:=c/hhv(h,20)>0.976;
- a4:=c>o and c/ref(c,1)>1.091;
- a5:=c/llv(c,40)<1.50;
- b1:=v/ref(v,1)>5.086;
- aa:=(a1 or b1) and a2 and a3 and a4 and a5;
- if(count(ref(aa,1),5)>=1,0,aa)